App - Script

Friday 29 July 2016, 19:52  #1
App - Script
kitto
  • 1 posts

Hello, I’m a new member in this forum, and I would like to know how to solve the following problem. I know the "vulnerability" is in the input() function, but I don’t know how to use it in order to find the password. I did a lot of attempts, but they were not successful. Also, I have a question. Does it remain functional? I mean, when I typed a number into the program, the program displayed an error called permission denied. It happened to me when the program tried to open .paswd. So I decided to try the same program on my computer, but it did not show the same error. Does anyone know why this happened ?