App - Script

Wednesday 7 March 2018, 05:24  #1
App - Script : Python Jail 1
jam
jam
  • 99 posts

Hi all,

I tried several things like bruteforcing in a while loop but could not escape. I found the address of exit function but there is still no hope to get out. There is nothing to run around as command and strings are not accepted. But i found the Exception e and the x variables are in string formats and can be output. Is there another way to carry out this baby ?

Saturday 7 April 2018, 22:39  #2
App - Script : Python Jail 1
jam
jam
  • 99 posts

Again Hi,

As i had written before, the address of exit function is given. I tried to debug a trivial executable and thought the given address could be a shared one, but it was not. Then, i tried to connect with the server by SSH client in the form of giving a command that should be executed remotely and it hang up. The result if it was executed, i have seen , i could manage a file in /tmp folder with permission 777 and by giving the command in SSH to write into but had no answer.
It makes me only saint angry. Every time when i was nearly giving up i found a solution by my own. Why should this one kick me back !

Thursday 19 April 2018, 01:47  #3
App - Script : Python Jail 1
jam
jam
  • 99 posts

hi all,

i got the flag. The hint is about builtin functions, which make the user able to read information about them. After all, there is still one hurdle to manage.

thx a lot,