App - System

By using %x I leaked the hex value of secret and changed its endianness. Something like this , if the leaked value is "4443424148474645" then after changing endianness it will be "ABCDEFGH" but when I try to submit that it says , "just try again " and hey just to confirm the length of the password is 12 , right ?

No  😊 The leaked value is 4x8 bits (32) in hex. You’ll need to re-order the bytes due to little endian format. After that you’ll get the same no. of bits , but re-ordered. This starts with "4470...." and ends with "....0000" . You need to convert from hex format to plain text to get the final flag.

Just a note, if someone is having trouble with this : you can find out the length of the string by looking at file it is stored. And if you are having hard time finding the string in memory, figure out what character is usually at the end of the file.